Afternoon all - Asking this on behalf of someone else, so please excuse my ignorance but...
How do you calculate taper ratio?
I've "Googled" it and not come up with much!!
Thanks all
[Edited on 19/2/08 by McLannahan]
What info have you got ?
and what form do you want the answer in ?
Thanks Mcerd - I'll check and post back!
Not that this means much to me but....
"It's a taper reamer that's 117mm long and 27mm thick at top. 10mm thick at the bottom"
and to add...
The form - I'd like to know whether it was a 1in8 or a 1in6 etc.. Dimensions may be slightly out!
Does that help?
Many thanks!
[Edited on 19/2/08 by McLannahan]
the difference in radius is 8.5 over a length of 117mm. Thats 1 in 13.76 or 4.155° per side, 8.31° included angle or 1 in 6.88 (both sides)
Edit to say that ball joint tapers are usually 1 in 6 ( or 2" per foot) 1 in 8 (1.5" per foot) or an included angle like 10°.
[Edited on 19-2-2008 by smart51]
Thanks Smart, I'll pass that on!
How is it actually worked out?
one number subtracted from antother, then divided by another.
e.g.
major radius minus minor radius divided by distance between them.
Thanks 02GF74 - That makes sense!
A = (D2 - D1)/2
ratio = A / B (or A in B )
in this case:
(27-10) /2 = 8.5
ratio = 8.5 in 117
divide both sides by 8.5 = 1 in 13.76
for the angle between the tapper and the central axis you've got a right angle triangle with:
the side opposite the angle 8.5
and the side adjacent to the angle is 117
so angle = Tan-1 (8.5 / 117) = 4.15°
and the included angle (ie from one side of the tapper to the other) is twice that = 8.31°
[edit]
damm, too slow...
[Edited on 19/2/08 by mcerd1]
Fantastic - Thanks guys!
those sizes could be imperial
at a guess:
10mm = 3/8"
27mm = 1 1/16"
117mm = 4 5/8"
giving 11/32 in 4 5/8
=> 1 in 13 7/16 or 1 in 13.45
=> 4.25° = 8.5° included angle
[Edited on 19/2/08 by mcerd1]
The plot thickens!
I'll double check!
the difference between 8.31° and 8.5° is only due to rounding errors from imperial to metric
and my figures are only a guess, (using your metric measurements to guess at a likely imperial size)
but it does appear to give a half sensable answer - but I could round them another way and get 8° or 9°
the only way to be sure is measure it accuratly (imperial or metric - doesn't matter)
Ive checked the Zeus book and it doesnt fit a std Morse Taper.
Thanks so much for all your help guys!
I wish I could begin to understand it!
It's a good thing I've never built a KC...It'd probably resemble a trebuchet!