McLannahan
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| posted on 19/2/08 at 12:39 PM |
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Calculate taper ratio??
Afternoon all - Asking this on behalf of someone else, so please excuse my ignorance but...
How do you calculate taper ratio?
I've "Googled" it and not come up with much!!
Thanks all
[Edited on 19/2/08 by McLannahan]
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mcerd1
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| posted on 19/2/08 at 12:49 PM |
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What info have you got ?
and what form do you want the answer in ?
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McLannahan
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| posted on 19/2/08 at 12:53 PM |
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Thanks Mcerd - I'll check and post back!
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McLannahan
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| posted on 19/2/08 at 12:56 PM |
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Not that this means much to me but....
"It's a taper reamer that's 117mm long and 27mm thick at top. 10mm thick at the bottom"
and to add...
The form - I'd like to know whether it was a 1in8 or a 1in6 etc.. Dimensions may be slightly out!
Does that help?
Many thanks!
[Edited on 19/2/08 by McLannahan]
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smart51
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| posted on 19/2/08 at 01:01 PM |
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the difference in radius is 8.5 over a length of 117mm. Thats 1 in 13.76 or 4.155° per side, 8.31° included angle or 1 in 6.88 (both sides)
Edit to say that ball joint tapers are usually 1 in 6 ( or 2" per foot) 1 in 8 (1.5" per foot) or an included angle like 10°.
[Edited on 19-2-2008 by smart51]
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McLannahan
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| posted on 19/2/08 at 01:05 PM |
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Thanks Smart, I'll pass that on!
How is it actually worked out?
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02GF74
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| posted on 19/2/08 at 01:44 PM |
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one number subtracted from antother, then divided by another.
e.g.
major radius minus minor radius divided by distance between them.
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McLannahan
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| posted on 19/2/08 at 01:52 PM |
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Thanks 02GF74 - That makes sense!
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mcerd1
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| posted on 19/2/08 at 01:53 PM |
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A = (D2 - D1)/2
ratio = A / B (or A in B )
in this case:
(27-10) /2 = 8.5
ratio = 8.5 in 117
divide both sides by 8.5 = 1 in 13.76
for the angle between the tapper and the central axis you've got a right angle triangle with:
the side opposite the angle 8.5
and the side adjacent to the angle is 117
so angle = Tan-1 (8.5 / 117) = 4.15°
and the included angle (ie from one side of the tapper to the other) is twice that = 8.31°
[edit]
damm, too slow...
[Edited on 19/2/08 by mcerd1]
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McLannahan
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| posted on 19/2/08 at 01:55 PM |
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Fantastic - Thanks guys!
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mcerd1
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| posted on 19/2/08 at 02:13 PM |
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those sizes could be imperial
at a guess:
10mm = 3/8"
27mm = 1 1/16"
117mm = 4 5/8"
giving 11/32 in 4 5/8
=> 1 in 13 7/16 or 1 in 13.45
=> 4.25° = 8.5° included angle
[Edited on 19/2/08 by mcerd1]
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McLannahan
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| posted on 19/2/08 at 02:28 PM |
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The plot thickens!
I'll double check!
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mcerd1
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| posted on 19/2/08 at 03:20 PM |
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the difference between 8.31° and 8.5° is only due to rounding errors from imperial to metric
and my figures are only a guess, (using your metric measurements to guess at a likely imperial size)
but it does appear to give a half sensable answer - but I could round them another way and get 8° or 9° 
the only way to be sure is measure it accuratly (imperial or metric - doesn't matter)
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DarrenW
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| posted on 19/2/08 at 03:23 PM |
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Ive checked the Zeus book and it doesnt fit a std Morse Taper.
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McLannahan
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| posted on 19/2/08 at 03:33 PM |
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Thanks so much for all your help guys!
I wish I could begin to understand it!
It's a good thing I've never built a KC...It'd probably resemble a trebuchet!
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