
In 2 books I've got, it gives a formula for calculating the turning circle as:
Tc = W/Sin L
Whers
Tc = Turning Circle
W = Wheelbase
L= Lock angle of the outside wheel.
I've done the maths on this (well ok, someone helped me....) and it comes up with an angle for the outside wheel of 14 deg - which seems
extremely small?
Is the equation wrong, does anyone know of an alternative, or am I just imagining needing more?!
[Edited on 8/10/07 by Delinquent]
i don't quite know how it applies to big cars, but on rc cars the inside wheel turns quite a bit more than the outside wheel.
also you didn't mention what the turning circle was to give 14 degrees
quote:
Originally posted by Delinquent
In 2 books I've got, it gives a formula for calculating the turning circle as:
Tc = W/Sin L
Whers
Tc = Turning Circle
W = Wheelbase
L= Lock angle of the outside wheel.
Seems likely such a formula would use the radius of the turning circle, although without drawing it out and thinking about it I couldn't say for
sure.
Would that give you a better answer?
Edit: Post above sounds correct, although tying in with what I said above, wheels at 90 degrees would in fact give you a turning circle of twice the
wheelbase.
i.e.
Tc = 2W/Sin(L)
[Edited on 8/10/07 by matt_claydon]
my apologies, I am at a base level being a bit of a retard - it clearly states later on that that gives the radius - which I came across only after
someone on another forum pointed it out a couple of minutes ago!
sorry about that!
One of the things in engineering that a simple graphical solution will give you a good answer -- with its own built in sanity check.