
I need to calculate the buckling load for a vertically mounted hydraulic cylinder in accordance with an agreed formulae from a British Standard.
Trouble is I need the Second Moment of Area of the cylinder rod in 4th power milimetres.
Sounds easy but I'm getting confused.
The cylinder rod is 60mm diameter.
Thanks,
John.
quote:
Originally posted by John P
Sounds easy but I'm getting confused.


is this any good
Area: 2827.4334
Perimeter: 188.4956
Bounding box: X: -30.0000 -- 30.0000
Y: -30.0000 -- 30.0000
Centroid: X: 0.0000
Y: 0.0000
Moments of inertia: X: 636172.5124
Y: 636172.5124
Product of inertia: XY: 0.0000
Radii of gyration: X: 15.0000
Y: 15.0000
Principal moments and X-Y directions about centroid:
I: 636172.5124 along [0.7071 0.7071]
J: 636172.5124 along [-0.7071 0.7071]
quote:
Originally posted by Aboardman
is this any good
Area: 2827.4334
Perimeter: 188.4956
Bounding box: X: -30.0000 -- 30.0000
Y: -30.0000 -- 30.0000
Centroid: X: 0.0000
Y: 0.0000
Moments of inertia: X: 636172.5124
Y: 636172.5124
Product of inertia: XY: 0.0000
Radii of gyration: X: 15.0000
Y: 15.0000
Principal moments and X-Y directions about centroid:
I: 636172.5124 along [0.7071 0.7071]
J: 636172.5124 along [-0.7071 0.7071]
some one else has to retake somecourse work then?!
Second moment of area for a solid circular section is (Pi)*(r^4)/4.
Using your diameter of 60mm this gives
Ixx = Iyy = 636200 mm^4
HTH,
Matt.
[Edited on 16/8/06 by matt_claydon]
quote:
Originally posted by matt_claydon
Second moment of area for a solid circular section is (Pi)*(r^4)/4.
Using your diameter of 60mm this gives
Ixx = Iyy = 10180000 mm^4
HTH,
Matt.
Yep, thanks for pointing that out - small mistake on my part ; corrected now!
quote:
Originally posted by RazMan
You lost me after the word 'calculate'