Ford XFlow

Can someone tell me what goes on between the solonoid and coil. I can see that we have what is effectively a big relay powered up by the red/black wire which becomes active when turning ignition.

What about the other terminal (yellow/black) that goes to the coil. At present there is no output from this. Should it become live once the engine is running, remain live whenever the ignition is on - or what? Mine is dead. Does that mean the solonoid is US?

If the solenoid gets the starter going, I wouldn't worry about it - simply take the coil's live feed to a convenient point in the 'switched' part of the 12v wiring (i.e. a circuit that's on when the ignition switch is in the run position).

My solenoid doesn't even have that extra terminal - just battery, starter and the start connector.

David

Its the 12v feed from the solenoid to the coil when the engine is being started. Should ony be live when you are cranking the engine.

You have a ballast resistor installed in the loom, which provides 9v to the coil when the ignition is on. This is over ridden by the 12v while starting to give a better spark. Was designed to increase ease of starting.

David

Good point - I'd forgotten the ballast resistor circuit!

I suspect that you may have a mix-up in this area, thinking of your other post (fried coil).

I didn't have a ballast circuit in my car, so I can't help you any further - I'll leave that to others.

David

As the coil is now buggered I think I'll get a 12V one and wire it to a convenient feed.