# Line slope calculator 5x+y=35

**Straight line given by points A[5; 10] and B[6; 5]**

## Calculation:

**Slope-intercept form of line:**y = -5x+35

**Canonical form of the line equation:**5x+y-35 = 0

**Parametric form of the line equation:**

x = t+5

y = -5t+10 ; t ∈ R

**Slope:**m = -5

**Slope angle of line: φ =**-78°41'24″ = -1.3734 rad

**X intercept:**x

_{0}= 7

**Y intercept:**y

_{0}= q = 35

**Distance line from the origin:**d

_{0}= 6.8641

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(1; -5)

**Normal vector: n =**(5; 1)

**Midpoint of the segment AB: M =**[5.5; 7.5]

**Perpendicular Bisector equation:**x-5y+32 = 0

**Vector OA = (5; 10) ; |OA| = 11.1803**

**Vector OB = (6; 5) ; |OB| = 7.8102**

**Scalar product OA .OB = 80**

**Angle ∠ AOB = 23°37'46″ = 0.4124 rad**